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-4.905x^2+8x+2=0
a = -4.905; b = 8; c = +2;
Δ = b2-4ac
Δ = 82-4·(-4.905)·2
Δ = 103.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{103.24}}{2*-4.905}=\frac{-8-\sqrt{103.24}}{-9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{103.24}}{2*-4.905}=\frac{-8+\sqrt{103.24}}{-9.81} $
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